Midpoint symmetry of a viscous Burgers step ($f(z,-Uz-\theta )=U-f(z,\theta )$)

The viscous Burgers step solution with negative flux is symmetric around $\theta =-Uz/2$ after subtracting $U/2$. Its Gaussian-tail ratio equals one precisely at this midpoint, giving $f=U/2$ for either sign of $U$. For $U>0$ this point becomes the entropy-shock center in the vanishing viscosity approximation; for $U<0$ it is the center of a rarefaction wave. The same trajectory therefore does not by itself identify a shock.