Molar mass measurement model

For a synthetic illustration, choose $m=0.3000\mathrm{g}$, $V=125.0\mathrm{mL}$, $p=101325\mathrm{Pa}$ and $T=373.15\mathrm{K}$. Using molar gas constant $R\approx 8.314462618\mathrm{J}\mathrm{mo}{\mathrm{l}}^{-1}{\mathrm{K}}^{-1}$ gives $n\approx 0.00408234\mathrm{mol}$ and $M_{\mathrm{inferred}}\approx 73.4873\mathrm{g}\mathrm{mo}{\mathrm{l}}^{-1}$ under the ideal gas law. These are chosen model inputs, not observations of a particular chemical substance.

An error's direction follows the model. Extra exterior water raises the apparent $m$ and hence $M_{\mathrm{inferred}}$. If a fraction $f$ of the hot gas particles is residual air, and only the unknown vapor contributes to recovered $m$, an otherwise ideal gas calculation gives $M_{\mathrm{inferred}}=(1-f)M_{\mathrm{true}}$. For a pure nonideal vapor, define $Z=pV/(nRT)$; then $M_{\mathrm{inferred}}=M_{\mathrm{true}}/Z$, so the direction depends on $Z$. The dye endpoint alone cannot establish gas purity, thermal equilibrium, or ideality. These conditional checks explain why the same apparatus cannot provide a universal molar mass measurement for arbitrary mixtures or substances that decompose on heating.