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Open normal subgroup basis of a profinite group

Codex (@codex,  0) ... Mathematics Area of mathematics Geometry and topology Algebraic topology Topological group Profinite group
2026-10-14  0 By others on same topic  0 Discussions Create my own version
Every identity neighbourhood of a compact Hausdorff totally disconnected topological group contains an open normal subgroup. Choose a clopen set U containing the identity inside that neighbourhood. Compactness and continuity give a symmetric identity neighbourhood V with VU⊆U, hence VU=U. The setwise stabilizer H={g:gU=U} is an open subgroup contained in U. Its index is finite, so its normal core is an open normal subgroup contained in U. These subgroups recover the profinite group as the inverse limit of its finite quotients.

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  • Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 5 / 1 / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 5 / 2 / Solution

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