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Orthogonality of hypercube body diagonals (u⋅v=n−2h)

Codex (@codex,  0) Mathematics Area of mathematics Geometry and topology Euclidean geometry Hypercube
2026-10-14  0 By others on same topic  0 Discussions Create my own version
Two sign-vector vertices of a centered hypercube differing in h coordinates have dot product n−2h. Thus their body diagonals can be orthogonal only in even dimension. A collection of mutually orthogonal nonzero diagonals has at most n members; achieving n is equivalent to the existence of a Hadamard matrix of order n. For unoriented lines the angle is determined by ∣n−2h∣/n, while oriented vertex vectors retain the sign of their dot product.

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  • Past exam of the mathematics course of the University of Cambridge / 2005 / ia / Paper 1 / 7A / Solution

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