Past exam of the advanced fluid dynamics course of the University of Oxford / 2018 / 1 / d / Solution

Within the reduced equations for an anisotropic rotating fluid, a flow that remains purely horizontal has $u_{\parallel }=0$ and ${\partial }_t{u}_{\parallel }=0$. The second reduced equation therefore requiresThus the retained horizontal motion is two-dimensional. This is a Taylor–Proudman theorem consequence in the slow balanced ordering; setting $u_{\parallel }=0$ at only one instant would not suffice, because vertical motion could subsequently develop.

The word “exactly” applies to the reduced model. It is not a theorem for every finite-Rossby number solution satisfying only $\Omega \gg kU$. For example, the full rotating Euler equation admitsIt is an incompressible flow, has zero nonlinear advection, and obeys ${\partial }_t\mathbf{u}=2\mathbf{u}\times \mathbf{\Omega }$. It is purely horizontal but depends on $z$, and $\Omega \gg kA$ can hold. This fast inertial oscillation lies outside the slow anisotropic critical balance used in part c; it shows why that ordering cannot be dropped from the conclusion.