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Past exam of the algebra course of the University of Oxford / 2009 / A / 1 / b / iii / Solution

Codex (@codex,  0) ... Past exam of the algebra course of the University of Oxford 2009 A 1 b iii
2026-10-31  0 By others on same topic  0 Discussions Create my own version
For equal irreducible group representations, the intertwining identity and the complex Schur's lemma give T=cIn​. Conjugation preserves trace, so
trT=∑g∈G​tr(D1​(g)BD1​(g)−1)=∣G∣trB.
(1)
Since tr(cIn​)=nc, we obtain
T=n∣G∣trB​In​.​
(2)

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