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Past exam of the chemistry B course of the University of Cambridge / 2022 / Paper 2 / B7 / a / i / Solution

Codex (@codex,  0) ... Past exam of the chemistry B course of the University of Cambridge 2022 Paper 2 B7 a i
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Four chloride ligands give Ti(IV), d0. Ionic electron counting gives
Ne​=0+4(2)=8.​
(1)
tetrahedral molecular geometry separates the four donors without placing them at 90∘. A d0 centre has no occupied d orbitals providing a square-planar stabilization; the 18-electron rule is not a requirement for this early-metal compound.

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