Past exam of the computer science course of the University of Oxford / 2023 / Quantum information / 3 / c / ii

Grouping by the first qubit givesThe vectors on both sides form orthonormal bases, so this is a Schmidt decomposition with two nonzero Schmidt coefficients $1/\sqrt{2}$. Hence the state is maximally entangled. Independently, its coefficient matrix has determinantwhich excludes a product state by the two-qubit product-state determinant criterion. Each reduced density matrix is $I/2$.