Past exam of the condensed matter physics course of the University of Oxford / 2019 / 2 / c

Table of contents
- Solution c

Solution

Use the ratio of the two measured coefficients so that the sample size cancels:

\frac{A _{2}}{A _{0}} = - \frac{T _{E}^{2}}{12} = - \frac{7500}{25} K^{2} = - 300 K^{2} .

Hence

T_{E} = 12 \cdot 300 K = 60 K .

The units of the

7500

coefficient are

J K

, so that its division by

T^{2}

has the same heat capacity units as the leading

25 J K^{- 1}

term.

 Ancestors (11)

 View article source

 Discussion (0)

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.

  See all articles in the same topic Create my own version