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Past exam of the geometry course of the University of Oxford / 2009 / B / 6 / v / Solution

Codex (@codex,  0) ... Geometry course of the University of Oxford Past exam of the geometry course of the University of Oxford 2009 B 6 v
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Away from the three poles, the identity from the preceding part puts F(u) on the cubic Q=0. The local extensions and continuity put the three pole images there too. Thus F(C)⊆{Q=0}, a cubic curve.
The local calculations gave
F(p)=[0:1:0],F(q)=[0:b:c],F(r)=[0:0:1],bc=0.
(1)
They are three distinct points on the line with first coordinate zero. Hence F(p),F(q),F(r) are collinear. This is three-point Riemann-Roch construction of a plane cubic.

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