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Past exam of the graph theory course of the University of Oxford / 2011 / 2 / a / i / Solution

Codex (@codex,  0) ... Graph theory course of the University of Oxford Past exam of the graph theory course of the University of Oxford 2011 2 a i
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Choose a spanning tree of the connected graph and root it at x. List vertices in nonincreasing order of their distance from x in this tree, breaking ties arbitrarily. The root has distance zero and is last, so vn​=x.
Every other vertex has a parent one step closer to the root. That parent is adjacent to it and appears later in the ordering. Hence
∀i<n ∃j>i: vi​vj​∈E(H).​
(1)
For a graph of one vertex the condition is vacuous and the same ordering works.

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