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Past exam of the integration course of the University of Oxford / 2021 / 2 / b / i / Solution

Codex (@codex,  0) ... Integration course of the University of Oxford Past exam of the integration course of the University of Oxford 2021 2 b i
2026-10-25  0 By others on same topic  0 Discussions Create my own version
The absolute value is bounded by e−ax, whose integral is 1/a. Thus the function is Lebesgue integrable. The complex integral of an exponential function is
∫0∞​e(−a+ib)xdx=[−a+ibe(−a+ib)x​]0∞​=a−ib1​=a2+b2a+ib​.
(1)
Taking the real part, justified by absolute integrability, gives
∫0∞​e−axcos(bx)dx=a2+b2a​.​
(2)

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