Use , the valuation ring of the completion of a number field at a prime ideal, with uniformizer and residue field . This completeness is essential for coprime-factor Hensel lifting. Normalize the two residue factors to be monic first; if the original factors have reciprocal leading units, undo the normalization by multiplying the eventual factors by reciprocal lifts of those units.
Let the two monic residue degrees be . Start with monic lifts satisfying . Suppose monic lifts of these degrees satisfy . Put , of degree less than . Over , the linear map
is injective: a zero image makes divide , by coprimality, forcing by its degree bound, and then . The dimensions agree, so this map is a bijection. Choose lifts whose image is , and set
Their product agrees with modulo ; the new cross term has factor and . The degree bounds preserve monicity. Each coefficient is a Cauchy sequence in the complete discrete valuation ring , so the limits satisfy
If were interpreted only as an ordinary localization rather than the completed valuation ring, the assertion would be false. For example splits modulo seven but is irreducible over . The completion notation in the next part provides the intended local-field interpretation.
Set and , with valuation rings . Let be the ramification index, the residue-field degree, and the residue characteristic. A base uniformizer generates in , up to a unit. The free -module has rank . For an integral , its field trace is the matrix trace of multiplication by on this module. Reduction modulo preserves the matrix trace.
The quotient has a filtration
Each of the successive quotients is a one-dimensional vector space over . On each, multiplication by acts as multiplication by its residue , whose trace over is . A basis adapted to the filtration makes the multiplication matrix block triangular, so its trace is the sum of these quotient traces. This proves trace reduction in a ramified local extension:
Since the hypothesis says , the right side is zero in . Thus
No normality hypothesis is needed. The original PDF only requires divisibility of , not divisibility exactly once; the converted TeX has corrupted that condition and several local subscripts.

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