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Past exam of the mathematics course of the University of Cambridge / 2002 / iii / Paper 20 / 6 / i / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 20 6 i
Created 2026-10-03 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
Write the adjunction as a natural bijection αC,D​:D(FC,D)→C(C,GD). The adjunction unit and adjunction counit are defined by
ηC​=αC,FC​(1FC​),εD​=αGD,D−1​(1GD​).
(1)
Naturality of α implies GF(u)ηC​=ηC′​u for u:C→C′ and vεD​=εD′​FG(v) for v:D→D′, so these are natural transformations 1C​→GF and FG→1D​. More explicitly, naturality at f:FC→D and g:C→GD gives the two transpose formulas
α(f)=G(f)ηC​,α−1(g)=εD​F(g).
(2)
These formulas will also prove the triangle identities for an adjunction.

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