The continuous dual space consists of bounded complex-linear functionals , with . For , consists of sequences with , norm ; consists of bounded sequences with supremum norm.
For , define on . Hölder's inequality gives absolute convergence and . For a finite truncation, choose for , zero elsewhere, interpreting the numerator as zero when . Its -norm is one and its pairing equals . Letting grow proves equality of the norms.
Conversely, for a bounded let . The same finite test vector gives , so . Finite truncations converge in , and continuity gives . Thus
For , boundedness gives , while any bounded sequence defines an absolutely convergent pairing bounded by . Density of finite sequences again proves surjectivity, and single-coordinate tests give norm equality. Hence The reversed argument fails for : finite sequences are not dense in its supremum norm; their closure is . For example the limit functional on convergent sequences extends by the Hahn-Banach theorem to , vanishes on every , yet takes value one on the constant-one sequence. It cannot be represented by pairing with an coefficient sequence.

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