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Past exam of the mathematics course of the University of Cambridge / 2008 / ii / Paper 4 / 9B / a / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2008 ii Paper 4 9B a
Created 2026-09-24 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
Take the sheet to lie in the x1​x2​ plane, with lengths a,b in those directions. Its surface density is M/(ab). Reflection symmetry about the coordinate axes makes the off-diagonal entries of the inertia tensor zero. Its principal moments of inertia are
I1​=abM​∫−a/2a/2​∫−b/2b/2​x22​dx2​dx1​=12Mb2​,
(1)
and similarly I2​=Ma2/12. Since I3​ integrates x12​+x22​, the perpendicular axis theorem gives
I1​=Mb2/12,I2​=Ma2/12,I3​=M(a2+b2)/12.​
(2)

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