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Past exam of the mathematics course of the University of Cambridge / 2009 / ia / Paper 4 / 12A / a / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2009 ia Paper 4 12A a
Created 2026-09-24 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
With no electric field, the Lorentz force is
F=qv×B.​
(1)
For nonrelativistic motion, the work-energy theorem gives
dtdK​=dtd​(21​m∣v∣2)=mv˙⋅v=F⋅v=q(v×B)⋅v=0.
(2)
Consequently K(t)=K(0)​. The reason is geometric: magnetic forces do no work because they are perpendicular to the instantaneous velocity. They can change its direction but not its magnitude. The same energy conclusion holds relativistically, using dE/dt=F⋅v and subtracting the constant rest energy to obtain kinetic energy.

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