The Baire category theorem states that a complete metric space is a Baire space: the intersection of countably many open dense sets is dense. Equivalently, a nonempty open subset cannot be a countable union of nowhere dense sets.
Let be open dense and any nonempty open set. Choose a closed ball of positive radius at most inside . Inductively choose inside the interior of intersected with , with positive radius at most . Density makes this intersection nonempty, and openness supplies a sufficiently small closed ball. The centres form a Cauchy sequence because all later centres lie in , whose diameter tends to zero. Completeness gives a limit . Since each ball is closed and contains all later centres, for every . Thus , proving density. Applying this to complements of the closures of nowhere dense sets gives the equivalent formulation.
If a linear subspace of a normed space contains an open ball , then and subtraction gives . For any , choose a positive scalar with . Then and hence . Thus . Every proper linear subspace has empty interior.
Let be the linear subspace of polynomials of degree at most . It has finite dimension , is proper in , and . For any norm on , the restricted norm on is equivalent to its coefficient Euclidean norm: on the coefficient unit sphere the continuous norm has a positive minimum and a finite maximum. Thus is complete. A complete subspace of a metric space is closed, since any sequence converging to an ambient limit is Cauchy and has the same limit in the subspace.
Part (b) makes each a closed set with empty interior, hence nowhere dense. If were a Banach space, this countable union would contradict the Baire category theorem. No norm makes the space of all polynomials complete.
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