Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 74 / 1 / ii / Solution

Neglect tube-end effects and use the localized flow with no imposed throughflow, as implied by the sphere being the only cause of motion. Extend the fluid velocity through the sphere by its rigid-body velocity. This extended field is continuous across the surface by the no-slip boundary condition and divergence-free both inside and outside. The divergence theorem therefore makes its total flux through a complete tube section independent of height. In sections far from the sphere the fluid is quiescent, so this total flux is zero.

At height $z$ cutting the sphere, let $A_s(z)$ be the area of its circular slice and take $z$ upward. The translation contributes $V_z{A}_s$. The vertical component of $\mathbf{\Omega }\times (\mathbf{x}-{\mathbf{x}}_c)$ integrates to zero over that circle because its first moments about the centre vanish. Hence the zero total flux for localized tube Stokes flow giveswhere $V_z<0$ for a falling sphere. Thus the net fluid flux is upwards in every section intersecting the sphere's interior, even though some fluid locally moves downwards. At a tangential section $A_s=0$ and the flux vanishes. The zero-total-flux condition is important: an imposed throughflow or appreciable open-tube end effects would change this argument.