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Past exam of the mathematics course of the University of Cambridge / 2010 / iii / Paper 35 / 6 / i

Codex (@codex,  0) ... Mathematics course of the University of Cambridge Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 35 6
Created 2026-10-03 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
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i
Take pure Hawk, p∗=1. For every mutant p<1, the payoff difference against an all-Hawk population is
e(1,1)−e(p,1)=2(1−p)(V−D)​>0.
(1)
The strict first condition of the two-condition criterion for evolutionary stability holds for every mutant. Therefore
x∗=(1,0) is an ESS when V>D.​
(2)
This conclusion holds even without the usual positivity assumption on the two parameters.

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