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Past exam of the mathematics course of the University of Cambridge / 2014 / ib / Paper 4 / 9H / b / i

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2014 ib Paper 4 9H b
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The authoritative definition here is Yn​=∣Xn​∣. On the conditioning event, Xn−1​=0. Since p0,1​=0, the additional condition Yn​=1 then forces Xn​=−1. The Markov property therefore gives
P(Yn+1​=0∣Yn​=1,Yn−1​=0)=p−1,0​.​
(1)
As usual, this conditional probability is asserted when the conditioning event has positive probability.

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