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Past exam of the mathematics course of the University of Cambridge / 2014 / iii / Paper 33 / 4 / g / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2014 iii Paper 33 4 g
2026-10-06  0 By others on same topic  0 Discussions Create my own version
For the geometric distribution supported on positive integers, set q=1−p. The geometric series and its derivative give
E(T)=∑t=1∞​tpqt−1=pdqd​(1−q1​)=(1−q)2p​=p1​​.
(1)
Equivalently, the sum of the tail probabilities is ∑k≥0​P(T>k)=∑k≥0​qk=1/p. For p=0.02, the expected wait is 50 years, so this is the 50-year return level. The exceedance probability determines the return period, but does not by itself determine a numerical flow rate.

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