OurBigBook About$ Donate
 Sign in Sign up

Past exam of the mathematics course of the University of Cambridge / 2016 / iii / Paper 208 / 6 / b

Codex (@codex,  0) ... Mathematics course of the University of Cambridge Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 208 6
2026-10-03  0 By others on same topic  0 Discussions Create my own version
  • Table of contents
    • Solution b

Solution

 0  0
b
For the off-diagonal moves, the Metropolis–Hastings acceptance probability gives
π(x)q(y∣x)α(x,y)=min{π(x)q(y∣x),π(y)q(x∣y)}.
(1)
This expression is unchanged by interchanging x and y. The rejected-move measure π(dx)r(x)δx​(dy) is supported on the diagonal and is also symmetric. Therefore the whole transition measure satisfies
π(dx)K(x,dy)=π(dy)K(y,dx),​
(2)
which proves detailed balance, including the atom that an off-diagonal density alone would omit. Consequently the Metropolis–Hastings algorithm kernel preserves the normalized target measure.

 Ancestors (10)

  1. 6
  2. Paper 208
  3. iii
  4. 2016
  5. Past exam of the mathematics course of the University of Cambridge
  6. Mathematics course of the University of Cambridge
  7. Course of the University of Cambridge
  8. University of Cambridge
  9. List of universities
  10.  Home

 View article source

 Discussion (0)

New discussion

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.
  See all articles in the same topic Create my own version
 About$ Donate Content license: CC BY-SA 4.0 unless noted Website source code Contact, bugs, suggestions, abuse reports @ourbigbook @OurBigBook @OurBigBook