Past exam of the mathematics course of the University of Cambridge / 2017 / iii / Paper 305 / 1 / a / Solution

Set $t_0=1$ and $t_i=-1$ for spatial indices. The complex conjugation of the scalar $i$ supplies a minus sign, while conjugating each of the three spatial gamma matrices supplies three more. In the original order,Consequently the chirality matrix obeysNo rearrangement of the gamma matrices is needed, so no additional anticommutator sign occurs. The star is entrywise complex conjugation, not matrix transpose or Hermitian conjugation.