Let and choose a local parametrization
whose derivative has rank . Define
This is a vector subspace because it is the image of a linear map, and rank gives .
If is another local parametrization through , the transition map is a local diffeomorphism. The chain rule gives
and is invertible, so . Thus the definition is independent of the parametrization. Equivalently, is the set of velocity vectors of smooth curves in through . This is the tangent space from a local parametrization.
After a fixed orthogonal change of ambient coordinates, a neighbourhood of in is the graph
of a smooth map . Write for all sufficiently large . Every tangent vector has the unique form
The convergence of implies convergence of its first component, say . Since and is continuous,
This proves the closedness of tangent spaces under convergent base points.
Conversely, suppose and write . Choose a nonzero and positive with . Then
and , . Every tangent vector arises as such a limit from distinct base points.
If , the first equation defines the ellipse
in the -plane, a smooth one-dimensional manifold, while defines a one-dimensional linear subspace in the -plane. Their product is a smooth manifold, parametrized by
so .
For , positivity of the first equation forces , and the second forces . Hence
a smooth line. Therefore
The answer is no. Let tend to zero and take
At a point with , differentiating the defining equations gives
Thus
for every , and . But is the -axis, so
Hence
The obstruction is the dimension jump in a smooth family of manifolds.

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