For a functional on a real Banach space, its convex conjugate is defined on the dual space by
Here is the dual pairing. For complex spaces, use its real part, equivalently regard the space as real for convex analysis. The convex conjugate is a convex function, being the supremum of affine functions of , even when itself is not convex.
Let . To prove convexity, take with finite values, , and . By the definition of infimum, choose with
Put and . Convexity of and gives
Let . If either endpoint value is infinite, the convexity inequality is automatic, and gives equality. Thus the infimal convolution of two convex functions is convex under the stated properness assumption. The proof uses approximate minimizing splits, so no attainment of the inner infimum is assumed.
For , the definition of the convex conjugate gives
where the substitution is a bijection of the independent pairs. Therefore
This infimal convolution identity does not need convexity of or attainment of the inner infimum. The assumptions ensure that both functions have nonempty effective domains; their conjugates never take , so the separated sum is well defined, allowing .
Write for the indicator functional of a constraint set and . Then
Both terms are convex, hence their infimal convolution is the convex squared distance to a convex set. The closest point theorem in a Hilbert space supplies the unique metric projection onto a closed convex set and gives .
Identify the Hilbert space with its dual space using the Riesz representation theorem. Completing the square yields , while is the support function. The conjugate of the squared distance to a convex set is therefore
For the closed unit ball, the metric projection onto a closed convex set is if , and otherwise. Therefore
The last equality uses the Cauchy-Schwarz inequality to compute the unit ball's support function, attained in the direction of when .

Articles by others on the same topic (0)

There are currently no matching articles.