For and , the characteristic function is
For a multivariate normal distribution with covariance matrix , the coordinates are uncorrelated and hence independent by independence of uncorrelated jointly normal variables. Therefore
This is the characteristic function of an isotropic Gaussian vector.
For an orthogonal matrix , invariance in distribution gives
The orthogonal group is transitive on each Euclidean sphere, so depends only on . Define
The continuity of a characteristic function makes continuous. Taking also gives , and hence
so is real-valued. Thus
as for every orthogonally invariant random vector.
Independence of the coordinates gives factorization of their joint characteristic function of a random vector. Orthogonal invariance under coordinate permutations makes all coordinate marginals identical. Hence, for and ,
Therefore
First, . For every ,
It cannot vanish: if for some , then
would imply for every positive integer , contradicting continuity at zero. Thus . Since every characteristic function has modulus at most one,
Now set . It is continuous, nonnegative, and additive:
The classification of a continuous additive function on the nonnegative real numbers gives , where . Consequently
Combining the preceding parts,
This is the characteristic function of . The uniqueness theorem for characteristic functions therefore gives
When , this means the degenerate distribution concentrated at the origin. This proves the Maxwell characterization of the normal distribution.

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