The second equation gives . The first then says either , giving the persistent equilibrium points and , orgiving and . These two points exist for .
At the origin the Jacobian matrix has trace and determinant , so it is stable for and a saddle point for . At the trace is and determinant , so it is stable for and a saddle for . Stationary bifurcations occur atwith the first two coinciding when .
At a non-axis fixed point the determinant and trace areThese formulas determine the solid stable and dashed unstable branches in the bifurcation diagram. The pair is born in a saddle-node bifurcation at . For , it exchanges branches with at and with at , both transcritical bifurcations. If , the saddle-node lies to the left of ; if , it lies to the right. For , the saddle-node and the collision at combine into a pitchfork bifurcation at .
Put , , and , adjoining . ThenThe zero eigenvalue has centre direction . Solving the center manifold invariance equation givesSubstitution yields the reduced equationIts equilibria are and for , exactly matching the three branches meeting at the pitchfork in part (b).
For small, has two negative eigenvalues and is a stable node. The two nearby equilibria satisfy and are saddles. Their stable and unstable separatrices form the local phase portrait; trajectories in the wedge between the stable manifolds approach , while trajectories crossing an unstable direction leave the neighbourhood.
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