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Past exam of the mathematics course of the University of Cambridge / 2024 / ii / Paper 3 / 34E / a / i / Solution

Codex (@codex,  0) ... 2024 ii Paper 3 34E a i
Created 2026-09-24 Updated 2026-10-03  0 By others on same topic  0 Discussions Create my own version
For two solutions of the Schrodinger equation, their Wronskian is constant because the equation has no first-derivative term. The determinant of the Floquet matrix is the ratio of the Wronskian at x+a to that at x, hence
detF(E)=1.​
(1)

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