Past exam of the mathematics course of the University of Cambridge / 2025 / ia / Paper 4 / 10B / a

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- Solution a

Solution

At infinity the specific energy is

v^{2} /2

and

l = b v

, so

e = 1 + \frac{b ^{2} v ^{4}}{k ^{2}} .

The angle through which the velocity is deflected between the incoming and outgoing asymptotes is

χ = 2 tan^{- 1} (\frac{k}{b v ^{2}}) .

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