For each crossing pair, delete one of its two edges. At most distinct edges are deleted, and the graph left behind has a crossing-free drawing. The planar graph edge bound therefore gives
so
This is the linear estimate underlying the crossing lemma.
Choose each vertex independently with probability
and take the induced drawing. Let its numbers of vertices, edges, and crossing pairs be . Since crossing edges have four distinct endpoints,
Part (i), with the harmless positive constant dropped, gives for every outcome. Taking expectations,
For , the right side is . Dividing by proves the crossing lemma estimate

Articles by others on the same topic (0)

There are currently no matching articles.