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Past exam of the mathematics course of the University of Oxford / 2015 / Prelims / Mathematics II / 3 / a / ii

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Oxford 2015 Prelims Mathematics II 3 a
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ii
Let TN​=∑n=1N​∣an​∣ and SN​=∑n=1N​an​. If (TN​) converges, it is a Cauchy sequence. Thus, for every ε>0, some N makes
∣Sq​−Sp​∣=​∑n=p+1q​an​​≤∑n=p+1q​∣an​∣=Tq​−Tp​<ε(q>p≥N),
(1)
where the triangle inequality gives the bound. Therefore (SN​) is a Cauchy sequence in the complex numbers. These form a complete metric space, so (SN​) has a finite limit of a sequence. Equivalently, apply the Cauchy criterion for series. Hence absolute convergence implies convergence.

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