Let be an arbitrary constant vector. By the cyclic identity for the scalar triple product,
Apply Stokes theorem to . Since is constant, the curl product identity gives
Consequently
For precision, the operator in the last line has components
The partial derivatives act on , with multiplying their values; they do not differentiate . Since the dot products agree for every constant , the cross-product form of Stokes theorem follows:
Here in the paper denotes the cross product, and the printed surface integral has its area element understood.

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