Use the Einstein summation convention, with repeated component indices summed. The following three expressions are listed separately below. For cyclic invariance of the trace,
where the middle equality commutes scalar entries, not the matrices themselves. If is invertible, this gives
This is similarity invariance of trace.
Taking the diagonal sum of the matrix product gives
Both repeated indices are summed from one to .
Apply row-column matrix multiplication twice:
The indices are free, while are summed.
The identity matrix has entries given by the Kronecker delta, so
Each of the diagonal entries is one.

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