Denote the unshifted differential expression by . The supplied Green's function satisfies , whereas the inhomogeneous equation is .
Multiply the latter equation by and the Green equation by , subtract and integrate in :The left-hand side is the boundary termIt vanishes because and satisfy the same homogeneous Robin boundary conditions. For example, where , substituting and cancels the endpoint expression; where , both values vanish. The other endpoint works identically. HenceThe Dirac delta function contribution is valid for an interior evaluation point ; equivalently, is continuous there and has flux-derivative jump .
This uses the existence of the unshifted Green's function stated in the question. Such a function is not automatic for every choice of and endpoint conditions: a nontrivial zero mode of would obstruct an ordinary inverse and would require a compatibility condition and a modified Green's function. Under the stated inverse assumption, the differential equation and the displayed integral equation are equivalent for functions in the boundary-condition domain.
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