Original question.
How do you account for the colours of a rainbow, of a soap-bubble, of mother-of-pearl ?
For a primary rainbow, sunlight is refracted into a water drop, internally reflected once, and refracted out. The refractive index varies with wavelength, producing optical dispersion. If is the incidence angle and the refracted angle, a spherical-drop ray has deviation
A stationary deviation concentrates neighbouring rays into a bright angular region. For visible light in water, the primary bow lies around from the antisolar direction, with red outside violet. Each observer receives the suitable colour from drops on the corresponding cone; the bow is not a fixed coloured object attached to one particular group of drops. Further internal reflections produce secondary bows with different angles and colour order.
A soap film uses thin-film interference. Rays reflected from its two surfaces acquire an optical path difference . With air on both sides of a nonabsorbing film, one of the surface reflections has a phase reversal. A constructive reflected condition is consequently
Different thicknesses, angles and wavelengths therefore give different reflected colours. A sufficiently thin symmetric film becomes dark because its leading reflected contributions cancel. The colour is chiefly an interference effect, rather than a pigment carried by the soap.
Mother-of-pearl, or nacre, has a structured arrangement of mineral tablets and organic layers. Repeated refractive-index contrasts produce wavelength-selective reflection; surface grooves can also act as diffraction gratings. Thus both multilayer interference and surface diffraction can contribute. A representative repeating-layer condition is . Modern structural-colour measurements and modelling distinguish these two contributions instead of treating every nacre appearance as a single grating effect.[ref] That microscopic account uses later structural evidence, not techniques available to an 1865 candidate.

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