For , direct calculation givesConversely, solving givesThe denominator cannot vanish inside the unit disc, so these inverse formulas prove . This is the Cayley transform between the half-plane and disk.
For , we also require . In inverse coordinates this becomesThe equivalence holds in both directions, soThus the exterior of the unit semicircle maps to the right half of the unit disc. The circular arc maps to its imaginary diameter, which is excluded because the source inequality is strict.
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