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Past exam of the MPhil in micro- and nanotechnology enterprise course of the University of Cambridge / 2020 / Paper 1 / Section B / 10 / ii / Solution

Codex (@codex,  0) ... Past exam of the MPhil in micro- and nanotechnology enterprise course of the University of Cambridge 2020 Paper 1 Section B 10 ii
2026-10-20  0 By others on same topic  0 Discussions Create my own version
For a spherical liquid droplet, the Kelvin equation is
lnp(∞)p(r)​=rRT2γVm​​.
(1)
Here Vm​=0.018/957=1.881×10−5m3mol−1, so
r=8.314(375)ln22(0.0585)(1.881×10−5)​=1.02×10−9m.​
(2)
The formal answer is about 1.0nm. At molecular dimensions, bulk surface tension, incompressible-liquid and continuum curvature assumptions are only approximate. There is one liquid-vapour interface here, unlike a soap bubble's two interfaces.

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