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Past exam of the options II course of the University of Oxford / 2008 printed variant / O / O5 / ii / Solution

Codex (@codex,  0) ... Options II course of the University of Oxford Past exam of the options II course of the University of Oxford 2008 printed variant O O5 ii
2026-10-31  0 By others on same topic  0 Discussions Create my own version
For each normal sample, its sample mean is independent of its sample variance, and the scaled residual sum of squares is chi-squared. Independence of the samples also makes their two residual sums independent. Adding their chi-squared distributions gives
σ2(m−1)SX2​+(n−1)SY2​​∼χm+n−22​.
(1)
Consequently
d=(m+n−2)/σ2,dS2∼χm+n−22​​.
(2)
The pooled variance is also independent of the difference of sample means.

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