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Past exam of the options II course of the University of Oxford
/
2009
/
C
/
C2
/
iv
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Year 2 of the mathematics course of the University of Oxford
Options II course of the University of Oxford
Past exam of the options II course of the University of Oxford
2009
C
C2
2026-10-31
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Solution
iv
Solution
0
0
0
iv
For
a
=
2
, the least positive
residues
in
Gauss lemma for quadratic residues
are simply
2
,
4
,
…
,
p
−
1
. The
number
exceeding
p
/2
is
s
=
2
p
−
1
−
⌊
4
p
⌋
.
(1)
For
p
≡
1
,
3
,
5
,
7
(
mod
8
)
, respectively, this count is even, odd, odd, even. Substituting these
parities
into the lemma gives
(
p
2
)
=
{
1
,
−
1
,
p
≡
1
,
7
(
mod
8
)
,
p
≡
3
,
5
(
mod
8
)
.
(2)
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(12)
C2
C
2009
Past exam of the options II course of the University of Oxford
Options II course of the University of Oxford
Year 2 of the mathematics course of the University of Oxford
Mathematics course of the University of Oxford
Undergraduate course of the University of Oxford
Course of the University of Oxford
University of Oxford
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