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Past exam of the options II course of the University of Oxford / 2012 / E / E3 / b / ii / 1 / Solution

Codex (@codex,  0) ... 2012 E E3 b ii 1
2026-10-31  0 By others on same topic  0 Discussions Create my own version
Take A1​=Q2. Every open disk contains infinitely many points with both coordinates rational, so every point of the plane is an accumulation point of A1​. Every disk also contains infinitely many points with an irrational first coordinate, and these lie in the complement. Thus
A1′​=R2=(R2∖A1​)′.​
(1)
The infinitely-many-points observation ensures that one can avoid the centre of the disk itself in both cases.

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