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Past exam of the options II course of the University of Oxford / 2012 / F / F2 / b / ii / Solution

Codex (@codex,  0) ... Past exam of the options II course of the University of Oxford 2012 F F2 b ii
2026-10-31  0 By others on same topic  0 Discussions Create my own version
By the implicit derivative formula,
h′(0)=−fy​(0,0)fx​(0,0)​=−1.
(1)
All sufficiently near points of the curve have y=h(x), and the only such point with x=0 is the origin itself. Therefore for the punctured approach along the curve,
(x,y)→(0,0)(x,y)∈C, (x,y)=(0,0)​lim​xy​=x→0lim​xh(x)−h(0)​=h′(0)=−1.​
(2)

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