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Past exam of the options II course of the University of Oxford / 2013 / M4 / c / Solution

Codex (@codex,  0) ... Year 2 of the mathematics course of the University of Oxford Options II course of the University of Oxford Past exam of the options II course of the University of Oxford 2013 M4 c
2026-10-31  0 By others on same topic  0 Discussions Create my own version
After a jump from one to k, the first return to one occurs exactly k steps later, with probability αk​. Later return times are sums of such positive-support values. Thus their greatest common divisor is
d=gcd{k:αk​>0}.
(1)
In an irreducible chain this is the common period of every state. Hence the chain is aperiodic exactly when d=1. A self-loop at one is sufficient but not necessary; support at two and three also has greatest common divisor one.

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