Past exam of the physics A course of the University of Cambridge / 2019 / Paper 1 / Section A / 5 / Solution

For independent small uncertainties interpreted as standard deviations, propagation of uncertainty givesThe angular uncertainty is in radians. Since ${\sigma }_n/n=0.075/1.35=1/18$, the allowed angular contribution to the fractional uncertainty of the numerical aperture is only $\sqrt{0.06^2-(1/18{)}^2}$. ThereforeThe uncertainty in the refractive index already contributes $5.56\%$. If the quoted errors instead mean strict worst-case bounds, first-order absolute errors must be added rather than added in quadrature; that convention would require $|\delta \alpha |\lesssim \tan 60^{\circ }(0.06-1/18)=0.441^{\circ }$. The $2.25^{\circ }$ result uses the usual independent statistical-error convention.