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Past exam of the short options course of the University of Oxford / 2023 / 1 / b / iii / Solution

Codex (@codex,  0) ... Short options course of the University of Oxford Past exam of the short options course of the University of Oxford 2023 1 b iii
2026-10-25  0 By others on same topic  0 Discussions Create my own version
The primes 2,5 both work, with the zero residue as a solution. For every other prime, multiplicativity of the Legendre symbol and quadratic reciprocity give
(p10​)=(p2​)(p5​)=(−1)(p2−1)/8(5p​).
(1)
The first factor is positive for p≡1,7(mod8); the second is positive for p≡1,4(mod5). They must have the same sign. The Chinese remainder theorem therefore yields
p=2,5orp≡1,3,9,13,27,31,37,39(mod40)​.
(2)

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