Expand a normalized product state asThus , , , , givingConversely the nonzero coefficient matrix has determinant zero precisely when it has rank one, so the condition also suffices for a pure two-qubit state to factor.
For any fixed pair of local measurement settings with operators , the Born rule factorizes:Hence a product state has independent local results in every pair of local bases. This assumes independent settings and local measurements; shared classical randomization of preparations or a subsequent joint interaction can generate correlations. A separable mixture is not necessarily a single product state.
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