Past exam of the year 1 of the computer science course of the University of Oxford / 2019 / Discrete mathematics, continuous mathematics, and probability resit / 6 / d

For iterates approaching ${\mathbf{x}}_{\ast }$, write $e_k=\Vert {\mathbf{x}}_k-{\mathbf{x}}_{\ast }\Vert$. Exact order of convergence $p$ means $e_{k+1}/e_k^p\to C$ for a finite constant $C>0$, with nonzero errors. Thus quadratic convergence has $p=2$, and cubic convergence has $p=3$. The weaker eventual bound $e_{k+1}\le C{e}_k^p$ means at least order $p$. Finite termination is a separate case.^[ref]

The assertion about being always faster is false. For example, the fixed-point iterations with errors $e_{k+1}=e_k^2$ and $d_{k+1}=50d_k^3$ have exact quadratic convergence and cubic convergence, respectively. Starting both at $0.1$, their next errors are $0.01$ and $0.05$: the cubic convergence method is worse on that step, although both converge. Error constants, starting points, and work per step all matter. The higher order of convergence describes asymptotic behavior within a convergence region, not a uniform comparison of all computations.