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Choose the poloidal magnetic field convention ${\mathbf{B}}_p=\nabla \times (A\hat{\mathbf{y}})=(-A_z,0,A_x)$. The term $\alpha B$ regenerates this poloidal flux function from the toroidal magnetic field through the alpha effect. It represents a component of the mean-field electromotive force produced by correlated velocity and magnetic fluctuations. The shear $G=\pi V/d$ stretches the poloidal vertical component $B_{p,z}=A_x$ into toroidal field, giving $G{A}_x$: this is the Omega effect. Both $\eta {\nabla }^2$ terms diffuse and damp the field. In a turbulent mean-field model, $\eta$ can denote an effective diffusivity including turbulent transport. The alpha-Omega dynamo approximation retains the shear-dominated toroidal source, and the kinematic dynamo assumption prescribes the velocity and coefficients without their Lorentz force feedback.

For a horizontal wavenumber $k$ and vertical wavenumber $\pi /d$, set $K^2=k^2+{\pi }^2/d^2$ and seek amplitudes proportional to $e^{st}$. The two modal equations areA nonzero mode requires the dispersion relationFor real nonzero $\alpha Gk$, the root with positive real square-root part isThe other root has strictly negative real part. For $k=0$ there is no oscillatory feedback and both roots have real part $-\eta {\pi }^2/d^2$; the possible triangular-system prefactor cannot yield exponential growth.

Let $h=|k|d/\pi >0$ and $D=\alpha V{d}^2/({\pi }^2{\eta }^2)$. The growing-branch exponent satisfiesConsequently the plane-layer alpha-Omega dynamo threshold at fixed $h$ isTo find its least value, differentiate $D_c(h)=2(h^{-1}+2h+h^3)$:The unique positive solution is $h^2=1/3$. The threshold diverges at both ends $h\downarrow 0$ and $h\to \infty$, so this is its global minimum. HenceWith the usual positive-$D$ convention, the onset value is $D_c=32/(3\sqrt{3})$ and exponentially growing waves exist for $D>D_c$. Exactly at the threshold the real part is zero, so it is a neutral dynamo wave: the quoted minimum is the onset threshold, or infimum for strict growth, not a growing solution at equality. If signed $D$ is allowed, the growth condition concerns $|D|$; there is no smallest signed negative value among all growing cases.

The real field is obtained by taking the real part of a Fourier mode. Its phase is $kx+(\Im s_{+})t+\pi z/d$, so the horizontal phase speed is $-(\Im s_{+})/k$. Reversing the sign of $\alpha V$ reverses propagation, while leaving the growth threshold unchanged. Reversing $k$ gives the conjugate real-field representation.