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An aromatic–aliphatic polyamide and methanol are formed. Let $\mathrm{Ar}=p\text{-}{\mathrm{C}}_6{\mathrm{H}}_4-{\mathrm{C}}_6{\mathrm{H}}_4\text{-}p$. The polymer repeat unit isEach amide linkage comes from nucleophilic acyl substitution: an amine attacks an ester carbonyl, the tetrahedral intermediate expels methoxide, and proton transfer produces methanol. There are approximately $2n$ molecules of methanol for $n$ complete repeat units in a long chain; the precise finite-chain count depends on its end groups. Removal of methanol drives this step-growth polymerization.

Gel permeation chromatography separates by solution hydrodynamic volume, rather than molar mass alone. At equal molar mass, a more extended chain accesses fewer pores and elutes earlier. The relatively rigid, conjugated poly(3-hexylthiophene) is the natural first-eluting candidate, compared with the more flexible chains, provided all samples are molecularly dissolved.

This is a structural prediction, not an unconditional ordering: solvent quality, polymer aggregation and column interactions affect retention, and the hydrogen-bonding polyamide may not dissolve adequately in tetrahydrofuran. An insoluble sample cannot be assigned an ordinary solution gel permeation chromatography elution time.

A differential refractive index detector can detect all four polymers when their refractive-index contrasts are nonzero. Light scattering with an appropriate concentration detector can additionally provide molar mass. A single ultraviolet detector is unsuitable as the universal detector because polypropylene lacks the strong chromophores present in the aromatic and conjugated products.