Positive invariant interval for a cubic biological population map ($F((0,3/2))\subset (0,3/2)$)

For $F(N)=(N-1/2)(N-1)(2-N)+1/2$, every positive initial value with $F(N_0)>0$ has positive subsequent iterates. Indeed $F(N)<3/2$ for every $N>0$, since $F(N)-3/2=-N(2N^2-7N+7)/2<0$. On $[0,3/2]$, the negative part of the cubic product has magnitude at most $3/8$, so $F(N)\ge 1/8$. Thus the first positive image enters the forward-invariant interval $(0,3/2)$.